A photon of wavelength 3000 Å strikes a metal surface. The work function of the metal is 2.13 eV . What is the kinetic energy of the emitted photoelectron? ( h =6.626 10⁻³⁴ Js )

Step-by-step solution

=3000 Å=3 10⁻⁷ ~m , =2.13 eV aligned & K.E. =h v- hv ₀= hv - = hc - & = (6.626 10⁻³⁴- 34 2 10^8 ) 3 10⁻⁷ - (2.13 1.6 10⁻¹⁹ ) & = 1.98 10⁻²⁵ 3 10⁻⁷ - (3.408 10⁻¹⁹ ) & = (6.60 10⁻¹⁹ )- (3.408 10⁻¹⁹ ) & =3.192 10⁻¹⁹ ~J & =2.0 eV aligned