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MHT CET202526 Apr 2025Evening ShiftChemistryChemical Bonding and Molecular StructureActual

Which of the following is correct decreasing order of bond length regarding N ₂, O ₂ and Cl ₂ ?

Options

  1. ACl ₂> O ₂> N ₂
  2. BCl ₂> N ₂> O ₂
  3. CO ₂> N ₂> Cl ₂
  4. DN ₂> O ₂> Cl ₂

Correct answer

A. Cl ₂> O ₂> N ₂

Step-by-step solution

Bond lengths decrease with increasing bond multiplicity and increase with larger atomic radii. The bond order and atomic size determine the bond length: N ₂ has a triple bond, O ₂ a double bond, and Cl ₂ a single bond. N ₂ : N N , bond length 109.8 pm O ₂ : O = O , bond length 121 pm Cl ₂ : Cl - Cl , bond length 199 pm Since higher bond order corresponds to shorter bonds, and chlorine has the largest atomic radius, the order is Cl ₂ > O ₂ > N ₂ .

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