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MHT CET202522 Apr 2025Morning ShiftChemistryChemical Bonding and Molecular StructureActual

Identify the correct statement regarding geometry and lone pair of electrons present in CH ₄ and SiCl ₄

Options

  1. ABoth have same geometry with two lone pair of electrons each.
  2. BBoth have different geometry with one lone pair of electrons each.
  3. CBoth have same geometry with no lone pair of electrons each.
  4. DBoth have different geometry with no lone pair of electrons each.

Correct answer

C. Both have same geometry with no lone pair of electrons each.

Step-by-step solution

Using VSEPR theory to analyze molecular geometry: For CH₄ and SiCl₄ , both central atoms ( C and Si ) belong to Group 14 and have 4 valence electrons, forming 4 single bonds with no remaining electrons for lone pairs. The steric number is 4 in both cases, resulting in tetrahedral geometry. Comparing the options: A) Incorrect: both have zero lone pairs B) Incorrect: geometries are identical, not different C) Correct: both exhibit tetrahedral geometry with no lone pairs D) Incorrect: geometries are identical, not dif

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