The wavelength of electron in the first orbit of hydrogen atom is 3.3 10⁻¹⁰ ~m . The kinetic energy of electron (in J ) is ( h =6.6 10⁻³⁴ Js , m _ e =9.0 10⁻³¹ ~kg )

Step-by-step solution

From de-Broglie's equation p = h or, v = h m K.E. = 1 2 mv ^2= 1 2 ~m h ^2 ~m ^2 (3.3 10⁻¹⁰ )^2 = 1 2 9 10⁻³¹ ( 6.6 10⁻³⁴ 3.3 10⁻¹⁰ )^2 aligned & = 2 9 10⁻¹⁷ ~J =0.222 10⁻¹⁷ ~J & =2.22 10⁻¹⁸ ~J aligned