The wavelength associated with the electron moving in the first orbit of hydrogen atom with velocity 2.2 10^6 ~ms ⁻¹ (in nm) is (m_e=9.0 10⁻³¹ ~kg , h=6.6 10⁻³⁴ Js )

Step-by-step solution

According to de-Broglie's equation, = h m v where, is wavelength h is Planck's constant (6.626 10⁻³⁴ Js )m is mass of electron (given 9.0 10⁻³¹ ~kg ) v is velocity of electron (given 2.2 10^6 ~m / s ) = 6.626 10⁻³⁴ 9.0 10⁻³¹ 2.2 10^6 =0.33 10⁻⁹ ~m i.e. 0.33 ~nm (as 1 ~nm =10⁻⁹ ~m )