Calculate the mass of an elementary particle, which is accelerated to twice the velocity of light with the precision 1 % and has 1.05 10⁻¹³ ~m uncertainty in position. (h=6.6 10⁻³⁴ ~kg ~m ^2 ~s ⁻¹ )

Step-by-step solution

Precision = 1 % Accuracy =0.01 aligned & v=3 10^8 2 100 =6 10^6 ~m / s & x=1.05 10⁻¹³ ~m aligned We know that, x v= h 4 m m= 6.626 10⁻³⁴ 4 1.05 10⁻¹³ 6 10^6 aligned & =0.08 10⁻²⁷ ~kg & =0.8 10⁻²⁸ ~kg aligned