Two particles of masses m and 2 m have equal kinetic energies. The de-Broglie wavelengths are in the ratio of

Step-by-step solution

As we know aligned & = h m v & = h 2 m E aligned [ E= 1 2 m v^2 ] Since, h is a constant and kinetic energy is same for both particles, so, aligned & = 1 m ₁= 1 m and ₂ & = 1 2 m aligned The ratio will be ₁ ₂ = 2 m m = 2 1 The ratio of de-Broglie wavelength is 2 : 1 .