AP EAMCET202120 Aug 2021Evening ShiftChemistryStructure of AtomActual
If the work function for the photoelectron emission of a metal is 3 . 75 eV , then the threshold wave length of the radiation needed for the ejection of the electron is approximately
Options
- A315   nm
- B280   nm
- C330   nm
- D290   nm
Correct answer
C. 330   nm
Step-by-step solution
Work function of metal ϕ = 3 . 75   eV = 3 . 75 × 1 . 6 × 10 - 19 V = 6 × 10 - 19 V Planck's constant h = 6 . 63 × 10 - 34 J . s Velocity of light c = 3 × 10 8   m / s Wavelength = hc ϕ = 6 . 63 × 10 - 34 × 3 × 10 8 6 × 10 - 19 = 331 . 5   × 10 - 9 m = 331 . 5   nm Hence, the threshold wave length of the radiation needed for the ejection of the electron is approximately 330   nm .