The element with outer electronic configuration ( n - 1 ) d 2 n s 2 , where n = 4 , would belong to

Step-by-step solution

We know that the general configuration of d - block element is ( n − 1 ) d 1 − 10 ns 1 − 2 where n is the period number. Here given electronic configuration is ( n - 1 ) d 2 ns 2 , where n = 4 . So, here the period number will be 4 . For d - block elements the group number can be found by adding no of electrons in n - 1 d sub-shell and the no of electrons present in the ns sub-shell. So, here group number will be 2 + 2 = 4 . Hence, the element belongs to 4 th  period and 4 th  group