Two thin circular discs A and B of radii 2 cm and 4 cm are in a liquid at the same depth. T A is the thrust on A and T B thrust on B . Then T A : T B =

Step-by-step solution

Thrust force is given by T h = v s u b ρ g                               v o l u m e = a r e a A × w i d t h t ⇒ T h = A t ρ g Here width( t ),density( ρ )ang g are same for both disc so T h ∝ A ⇒ T h A T h B = A A A B ⇒ T h A T h B = π r A 2 π r B 2 ⇒ T h A T h B = 2 2 4 2 = 1 4