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AP EAMCET202021 Sep 2020Evening ShiftChemistryStructure of AtomActual

Calculate energy of half mole of photons of a radiation with frequency (3 10¹² ~Hz ).

Options

  1. A(598.2 ~kJ ~mol ⁻¹ )
  2. B(0.598 ~kJ ~mol ⁻¹ )
  3. C(1.196 ~kJ ~mol ⁻¹ )
  4. D(119.6 ~kJ ~mol ⁻¹ )

Correct answer

B. (0.598 ~kJ ~mol ⁻¹ )

Step-by-step solution

Energy of a photon, (E=h v ), where, (v= ) frequency (=3 10¹² ~Hz ) Therefore, energy (=6.6 10⁻³⁴ 3 10¹² ~Hz =1.9878 10⁻²¹ ~J ) 1 mole (=6.02 10²³ ) photons, therefore, ( 1 2 ) mole (=3.01 10²³ ) photons Therefore, energy of ( 1 2 ) mole of photons ( aligned & =1.9878 10⁻²¹ 3.01 10²³ & =0.5982 ~kJ / mol aligned ) Hence, the correct option is (b).

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