If the kinetic energy of an electron of mass (9.0 10⁻³¹ ~kg ) is (2.0 10⁻²⁵ ~J ), the wavelength of the electron in ( nm ) is approximately

Step-by-step solution

Given, Kinetic energy of an electron (=2.0 10⁻²⁵ ~J ) Mass of electron (=9.0 10⁻³¹ ~kg ) Wavelength of the electron (= ) ? ( aligned & = h 2 m( KE ) ( here, h=6.6 10⁻³⁴ Js ) & = 6.63 10⁻³⁴ Js 2 9.0 10⁻³¹ ~kg 2 10⁻²⁵ ~J & =1.1043 10⁻⁶ ~m = 1.1043 10⁻⁶ 10⁻⁹ ~nm & =1104.3 ~nm aligned )