Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET201920 Apr 2019Evening ShiftChemistryStructure of AtomActual

The energy associated with Bohr's orbit in the hydrogen atom is given by the expression, E_n=- 13.6 n^2 eV . The energy in eV associated with the orbit having a radius 9 r₁ is ( r₁ is the radius of the first orbit)

Options

  1. A-13 6
  2. B-6.8
  3. C-1.51
  4. D-1.36

Correct answer

C. -1.51

Step-by-step solution

Given, Energy associated with Bohr's orbit in the hydrogen atom E_n=- 13.6 n^2 eV Now, radius of Bohr's orbit, r_n=0.529 n^2 Z Å or r_n=r₁ n^2[ Z=1 for hydrogen ] Given, or r_n=9 r₁r₁ n^2=r₁ 9 or n^2=9 or n=3 So, the energy associated with the orbit of radius 9 r₁ can be given as: aligned & E₉=- 13.6 9 eV =-1.51 eV & E₉=-1.51 eV aligned

Practice Structure of Atom on Quantrex Academy →

More from Structure of Atom

The frequency of photon which is emitted during a transition of electron of He ^+ ion from fifth energy level to third energy level will be: 2026Which of the following statement is correct ? 2026The wavelength of a particular electron transition for He ⁺ is 100 nm. The wavelength (in Å ) of H atom for the same transition is 2025The energy of second Bohr orbit of hydrogen atom is -3.4 eV. The energy of the fourth Bohr orbit of the He ⁺ ion will be 2025The work function of Cu is 7.68 10⁻¹⁹ ~J . If photons of wavelength 221 nm are made to strike the surface of the metal, the kinetic energy (in J) of the ejected electrons will be ( 2025In an element with atomic number (Z) 25 , the number of electrons with ( n+l ) value equal to 3 and 4 are x and y respectively. The value of (x+y) is 2025a , b , c , d are electromagnetic radiations. Frequencies of a , b are 3 10¹⁵ ~Hz , 2 10¹⁴ ~Hz , respectively, whereas wavelength of c, d are 400 ~nm , 750 ~nm , respectively. The 2025The number of electrons with magnetic quantum number, m _l=0 in the elements with atomic numbers Z=24 and Z=29 are respectively 2025 Full Structure of Atom list All AP EAMCET PYQs