When a metal surface is exposed to certain frequency of electromagnetic radiation. The kinetic energy of electron ejected from metal surface is 0.20 eV . If its work function (W₀ ) is 4.80 eV , the approximate frequency of radiation falling on the metal surface in Hz is

Step-by-step solution

Given, work function ( ₀ ) i.e. energy for ejection =4.80 eV and kinetic energy of the ejected electron. ( KE )=0.20 eV . According to photoelectric current relation. Total energy aligned Y (E_T ) & = ₀ t+ KE =4.80+0.20 E_T & =5.0 eV aligned aligned & E_T=5.0 eV & Also, 1 eV =1.6021 10⁻¹⁹ ~J & 5 eV =8.010 10⁻¹⁹ ~J & or & E_T=8.010 10⁻¹⁹ ~J & aligned aligned & and frequency ( v )= E_T( Total energy ) h( Planks constant ) & ( where, h=6.6260 10 ~m ^2 ~kg / s ) & V= E_T h = 8.010 10⁻¹⁹ 6.626 10⁻³⁴ aligned V= E_T h = 8