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AP EAMCET201822 Apr 2018Evening ShiftChemistryStructure of AtomActual

The wavelength corresponding to electronic transition between two orbits of hydrogen atom is 912 Å . The wavelength (in Å ) for the same electronic transition in Li ²⁺ is

Options

  1. A101.3
  2. B202.6
  3. C303.9
  4. D50.65

Correct answer

A. 101.3

Step-by-step solution

E= h c , i.e. E 1 and E Z^2 n^2 For same value of (n) E Z^2 Thus, E Z^2 1 where, E= energy, = wavelength Z= atomic number Therefore, Z_ ( H ) =1 aligned Z_ ( Li ) & =3 _ ( H ) =912 Å _ ( Li ) & = To find Z_ ( H ) ^2 Z_ ( Li ) & = _ ( Li ) _ ( H ) or _ ( Li ) = 1 912 9 _ ( Li ) & =101.3 Å aligned Hence, wavelength =101.3 Å

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