AP EAMCET201726 Apr 2017Morning ShiftChemistryStructure of AtomActual
The energy and radius of electron present in second orbit of He ⁺ respectively are
Options
- A-1.09 10⁻¹⁸ ~J , 105.8 pm
- B-8.72 10⁻¹⁸ ~J , 211.6 pm
- C-4.36 10⁻¹⁸ ~J , 52.9 pm
- D-2.18 10⁻¹⁸ ~J , 105.8 pm
Correct answer
D. -2.18 10⁻¹⁸ ~J , 105.8 pm
Step-by-step solution
aligned & For He ⁺: Z=2, n=2 & E_n=-2.18 10⁻¹⁸ Z^2 n^2 J & E_n=-2.18 10⁻¹⁸ 4 4 & =-2.18 10⁻¹⁸ ~J & r_n=52.9 n^2 Z pm =52.9 4 2 =105.8 pm & aligned