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AP EAMCET2014ChemistryStructure of Atom

In an atom the order of increasing energy of electrons with quantum numbers (i) n=4, l=1 (ii) n=4, l=0 (iii) n=3, l=2 and (iv) n=3, l=1 is

Options

  1. Aiii < (i) < iv < ii
  2. Bii < iv < i < iii
  3. Ci < iii < ii < iv
  4. Div < ii < iii < i

Correct answer

D. iv < ii < iii < i

Step-by-step solution

The order of increase of energy can be calculated from (n+I) rule. If two orbitals have same value of (n+I) , the orbital with lower value of n will be filled first. (i) For n=4, I=1,(n+I)=4+1=5 (ii) For n=4, l=0,(n+l)=4+0=4 (iii) For n=3, l=2,(n+l)=3+2=5 (iv) For n=3, I=1,(n+I)=3+1=4 Therefore correct order is (iv) < (ii) < (iii) < (i).

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