Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
AP EAMCET2002ChemistryStructure of Atom

The energy of an electromagnetic radiation is 19.875 10⁻¹³ ergs. What is its wave number in cm ⁻¹ ? (h=6.625 10⁻²⁷ . erg sec, .c=3 10¹⁰ ~cm sec ⁻¹ )

Options

  1. A1000
  2. B10^6
  3. C100
  4. D10000

Correct answer

D. 10000

Step-by-step solution

aligned & E=h v=h c =h c v & v = E h c = 19.875 10⁻¹³ 6.625 10⁻²⁷ 3 10¹⁰ =10^4 aligned

Practice Structure of Atom on Quantrex Academy →

More from Structure of Atom

The frequency of photon which is emitted during a transition of electron of He ^+ ion from fifth energy level to third energy level will be: 2026Which of the following statement is correct ? 2026The wavelength of a particular electron transition for He ⁺ is 100 nm. The wavelength (in Å ) of H atom for the same transition is 2025The energy of second Bohr orbit of hydrogen atom is -3.4 eV. The energy of the fourth Bohr orbit of the He ⁺ ion will be 2025The work function of Cu is 7.68 10⁻¹⁹ ~J . If photons of wavelength 221 nm are made to strike the surface of the metal, the kinetic energy (in J) of the ejected electrons will be ( 2025In an element with atomic number (Z) 25 , the number of electrons with ( n+l ) value equal to 3 and 4 are x and y respectively. The value of (x+y) is 2025a , b , c , d are electromagnetic radiations. Frequencies of a , b are 3 10¹⁵ ~Hz , 2 10¹⁴ ~Hz , respectively, whereas wavelength of c, d are 400 ~nm , 750 ~nm , respectively. The 2025The number of electrons with magnetic quantum number, m _l=0 in the elements with atomic numbers Z=24 and Z=29 are respectively 2025 Full Structure of Atom list All AP EAMCET PYQs