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MHT CET202615 April 2026Morning ShiftChemistryHydrocarbonsActual

Identify the compound formed when But-2-ene is treated with KMnO ₄ in dilute H ₂ SO ₄ .

Options

  1. AButanoic acid
  2. BAcetic acid
  3. CButanal
  4. DButanol

Correct answer

B. Acetic acid

Step-by-step solution

But-2-ene has the structure CH ₃- CH = CH - CH ₃ . When treated with acidic KMnO ₄ ( KMnO ₄ in dilute H ₂ SO ₄ ), it undergoes oxidative cleavage. The strong oxidizing agent completely breaks the carbon-carbon double bond, oxidizing each of the resulting fragments into a carboxylic acid. CH ₃- CH = CH - CH ₃ KMnO ₄, H ^+ 2 CH ₃ COOH The product formed is acetic acid (ethanoic acid). Answer: Acetic acid

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