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MHT CET202523 Apr 2025Morning ShiftChemistryHydrocarbonsActual

Identify product ' B ' in the following sequence of reactions. 1,2 Dibromoethane [ alcohol ] KOH ~A sodamide B

Options

  1. ABromoethane
  2. BBromoethene
  3. CEthene
  4. DEthyne

Correct answer

D. Ethyne

Step-by-step solution

1,2-Dibromoethane undergoes dehydrohalogenation with alcoholic KOH, producing bromoethene (vinyl bromide) through elimination of one molecule of HBr: CH₂ Br-CH₂ Br [ alc. KOH ] CH₂=CHBr + KBr + H₂ O . Bromoethene then reacts with sodamide ( NaNH₂ ), a strong base, to undergo further dehydrohalogenation, yielding ethyne (acetylene): CH₂=CHBr [ NaNH₂ ] HCCH + NaBr + NH₃ . Product B is ethyne. Among the options, D) Ethyne is correct.

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