There are two different solutions, A and B. The pH of solution A is 4. Find the pH of solution B having [ H ^+] three times that of solution A.

Step-by-step solution

The pH of solution A is given as 4 . [ H ^+]_A = 10⁻⁴ M For solution B, the hydrogen ion concentration is three times that of solution A. [ H ^+]_B = 3 [ H ^+]_A = 3 10⁻⁴ M pH of solution B = - [ H ^+]_B pH = - (3 10⁻⁴) pH = 4 - 3 Using 3 = 0.4771 : pH = 4 - 0.4771 = 3.5229 Answer: 3.5229