MHT CET202620 April 2026Morning ShiftChemistryIonic EquilibriumActual
Calculate the pOH of 0.01 M monobasic acid that is completely dissociated, at 298 K.
Options
- A02
- B12
- C03
- D11
Correct answer
B. 12
Step-by-step solution
For a completely dissociated monobasic acid, the concentration of hydrogen ions is equal to the concentration of the acid. [H^+] = 0.01 M = 10⁻² M The pH of the solution is calculated as: pH = - [H^+] = - (10⁻²) = 2 At 298 K, the relationship between pH and pOH is: pH + pOH = 14 Substituting the value of pH: pOH = 14 - 2 = 12 Answer: 12