Calculate the molar concentration of weak monobasic acid if K_a = 1.8 10⁻⁵ and degree of dissociation is 0.01 ?

Step-by-step solution

For a weak monobasic acid, the dissociation constant is given by: K_a = C ^2 1- Since = 0.01 , which is very small compared to 1 , we can approximate 1- 1 . K_a = C ^2 Rearranging for C : C = K_a ^2 Substituting the given values: C = 1.8 10⁻⁵ (0.01)^2 C = 1.8 10⁻⁵ 10⁻⁴ C = 1.8 10⁻¹ M Answer: 1.8 10⁻¹