MHT CET202617 April 2026Evening ShiftChemistryIonic EquilibriumActual
The solubility of sapringly soluble salt AB ₂ is 18 78 10⁻⁴ g/dm ^3 What is its solubility product ? (Molar mass of AB ₂ = 187 8 g mol ⁻¹ )
Options
- A2 10⁻¹⁵
- B4 10⁻¹⁵
- C6 10⁻¹⁵
- D8 10⁻¹⁵
Correct answer
B. 4 10⁻¹⁵
Step-by-step solution
Solubility S in mol dm ⁻³ is calculated by dividing the solubility in g dm ⁻³ by the molar mass. S = 18 78 10⁻⁴ 187 8 = 10⁻⁵ mol dm ⁻³ The dissociation of the salt AB ₂ is given by: AB ₂ A ²⁺ + 2 B ⁻ The solubility product K_ sp is: K_ sp = [ A ²⁺][ B ⁻]^2 = (S)(2S)^2 = 4S^3 Substituting the value of S : K_ sp = 4 (10⁻⁵)^3 = 4 10⁻¹⁵ Answer: 4 10⁻¹⁵