MHT CET202615 April 2026Evening ShiftChemistryIonic EquilibriumActual

Calculate pOH of 0.001M HCl solution.

Options

Correct answer

A. 11

Step-by-step solution

HCl is a strong acid and dissociates completely in aqueous solution. [H^+] = 0.001 M = 10⁻³ M pH = - [H^+] = - (10⁻³) = 3 Using the relation pH + pOH = 14 pOH = 14 - 3 = 11 Answer: 11

Practice Ionic Equilibrium on Quantrex Academy →

More from Ionic Equilibrium

At 30°C the solubility of PbI₂ salt in 0.2 M KI solution will be X, if the solubility product of PbI₂ at 30°C is 2.4 10⁻⁸ . Identify the value of X. 2026 A 0.15 mole of pyridinium chloride has been added to 500 cm ^3 of 0.2 M pyridine solution (a base). Assuming there is no change in volume upon mixing(Given: pK_b of pyridine = 8.82 2026 At T ( K ) K _ sp of two ionic salts MX ₂ and MX is 5 10⁻¹³ and 1.6 10⁻¹¹ respectively. The ratio of molar solubility of MX ₂ and MX is 2025 The conjugate base of phosphorus acid is x . The conjugate base of oleum is y . What are x and y , respectively? 2025 The molar solubility of PbI ₂ in 0.2 M Pb ( NO ₃ )₂ solution in terms of K _ sp (solubility product) is 2025 When 30 mL of 0.2 M NH ₄ OH is added to 30 mL of 2 M NH ₄ Cl solution. If the pH of the buffer formed is 8.2, what is the pK _ b of NH ₄ OH ? 2025 The percentage of ionization of 1 L of x M acetic acid is 4.242 and is called solution "A". The percentage of ionization of 1 L of y M acetic acid is 3 and is called solution "B". 2025 At 25^ C , the percentage of ionization of ' x ' M acetic acid is 4.242. What is the value of x ? ( ~K _ a =1.8 10⁻⁵ ) 2025 Full Ionic Equilibrium list All MHT CET PYQs