MHT CET202615 April 2026Evening ShiftChemistryIonic EquilibriumActual
What is the solubility product of binary sparingly soluble salt BA if 100 mL saturated solution of salt consist 10⁻⁴ moles at room temperature?
Options
- A1 10⁻⁴
- B1 10⁻⁶
- C1 10⁻⁸
- D1 10⁻¹⁰
Correct answer
B. 1 10⁻⁶
Step-by-step solution
The solubility S of the salt is the number of moles dissolved per litre of the saturated solution. Given moles of salt = 10⁻⁴ and volume = 100 mL = 0.1 L. S = 10⁻⁴ 0.1 = 10⁻³ mol L ⁻¹ For a binary salt BA , the dissociation is: BA B⁺ + A⁻ The solubility product K_ sp is given by: K_ sp = [B⁺][A⁻] = S S = S^2 Substituting the value of S : K_ sp = (10⁻³)^2 = 1 10⁻⁶ Answer: 1 10⁻⁶