MHT CET202615 April 2026Morning ShiftChemistryIonic EquilibriumActual
The solubility of sparingly soluble salts MX ₁ , MX ₂ and MX ₃ is 1 10⁻³ mol/L. Hence, their respective solubility products are
Options
- A1 10⁻⁶ , 4 10⁻⁹ and 27 10⁻¹²
- B1 10⁻⁹ , 4 10⁻⁹ and 32 10⁻¹²
- C1 10⁻⁹ , 8 10⁻⁸ and 32 10⁻¹²
- D1 10⁻⁶ , 8 10⁻⁸ and 27 10⁻¹²
Correct answer
A. 1 10⁻⁶ , 4 10⁻⁹ and 27 10⁻¹²
Step-by-step solution
For the salt MX ₁ (type AB ): MX ₁ M ^+ + X ^- K_ sp = S^2 Substituting S = 1 10⁻³ mol/L: K_ sp = (1 10⁻³)^2 = 1 10⁻⁶ For the salt MX ₂ (type AB ₂ ): MX ₂ M ²⁺ + 2 X ^- K_ sp = (S)(2S)^2 = 4S^3 Substituting S = 1 10⁻³ mol/L: K_ sp = 4(1 10⁻³)^3 = 4 10⁻⁹ For the salt MX ₃ (type AB ₃ ): MX ₃ M ³⁺ + 3 X ^- K_ sp = (S)(3S)^3 = 27S^4 Substituting S = 1 10⁻³ mol/L: K_ sp = 27(1 10⁻³)^4 = 27 10⁻¹² Answer: 1 10⁻⁶ , 4 10⁻⁹ and 27 10⁻¹²