What is the relationship between the degree of dissociation of a weak base and its concentration?

Step-by-step solution

For a weak base BOH , the dissociation reaction is BOH B^+ + OH^- . Let the initial concentration be C and the degree of dissociation be . At equilibrium, the concentrations are [BOH] = C(1- ) , [B^+] = C , and [OH^-] = C . The base dissociation constant K_b is given by K_b = [B^+][OH^-] [BOH] = C C C(1- ) = C ^2 1- . For a weak base, is very small compared to 1 , so 1- 1 . Thus, K_b C ^2 = K_b C . Therefore, the degree of dissociation of a weak base is inversely proportional to the square root of its concentration