MHT CET202611 April 2026Evening ShiftChemistryIonic EquilibriumActual
What is the solubility of BaSO ₄ in g / dm ^3 if its solubility product is 1.0 10⁻¹⁰ at 25^ C. [Molar mass of BaSO ₄ = 233 g/mol]
Options
- A2.33 10⁻³ g/ dm ^3
- B4.66 10⁻³ g/ dm ^3
- C3.48 g/ dm ^3
- D1.16 10⁻³ g/ dm ^3
Correct answer
A. 2.33 10⁻³ g/ dm ^3
Step-by-step solution
Let the solubility of BaSO ₄ be s mol/ dm ^3 . The dissociation reaction is: BaSO ₄(s) Ba ²⁺(aq) + SO ₄²⁻(aq) The solubility product K_ sp is given by: K_ sp = [ Ba ²⁺][ SO ₄²⁻] = s s = s^2 Substituting the given value of K_ sp : s^2 = 1.0 10⁻¹⁰ s = 1.0 10⁻⁵ mol/ dm ^3 To find the solubility in g/ dm ^3 , multiply the molar solubility by the molar mass of BaSO ₄ : Solubility = s Molar mass Solubility = 1.0 10⁻⁵ 233 Solubility = 2.33 10⁻³ g/ dm ^3 Answer: 2.33 10⁻³ g/ dm ^3