MHT CET202523 Apr 2025Morning ShiftChemistryIonic EquilibriumActual
Solubility of binary sparingly soluble salt is 1.12 10⁻⁴ ~g / dm ^3 . Calculate its solubility product (molar mass of salt =112 ~g ~mol ⁻¹ )
Options
- A1 10⁻³
- B1 10⁻⁶
- C1 10⁻⁹
- D1 10⁻¹²
Correct answer
D. 1 10⁻¹²
Step-by-step solution
The molar solubility S is determined from the given solubility and molar mass: S = 1.12 10⁻⁴ , g/L 112 , g/mol = 1.00 10⁻⁶ , M For the binary salt MX , dissociation follows MX(s) M^+(aq) + X^-(aq) yielding [M^+] = S and [X^-] = S . The solubility product is then K_ sp = [M^+][X^-] = S^2 = (1.00 10⁻⁶)^2 = 1.00 10⁻¹² The value of K_ sp is thus 1 10⁻¹² , corresponding to option D .