MHT CET202522 Apr 2025Evening ShiftChemistryIonic EquilibriumActual
The solubility product of NiS is 4.9 10⁻⁵ at 298 K. Calculate its solubility in mol~ dm ⁻³ at the same temperature?
Options
- A1.69 10⁻³
- B7.0 10⁻³
- C2.45 10⁻³
- D6.18 10⁻³
Correct answer
B. 7.0 10⁻³
Step-by-step solution
Dissolution of NiS: The dissolution equilibrium is NiS(s) Ni ²⁺ (aq) + S ²⁻ (aq) . Let s be the molar solubility in mol ,dm ⁻³ . At equilibrium, [ Ni ²⁺] = s and [ S ²⁻] = s . The solubility product is K _ sp = [ Ni ²⁺][ S ²⁻] = s^2 . Given K _ sp = 4.9 10⁻⁵ , solve s^2 = 4.9 10⁻⁵ for s . s = 4.9 10⁻⁵ = 49 10⁻⁶ = 7 10⁻³ , mol ,dm ⁻³ . This value corresponds to option B. Final answer: B