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MHT CET202522 Apr 2025Morning ShiftChemistryIonic EquilibriumActual

The solubility of sparingly soluble salt AX ₂ is 1 10⁻⁴ ~mol~ dm ⁻³ at 298 K . Calculate its solubility product?

Options

  1. A2 10⁻¹²
  2. B4 10⁻¹²
  3. C2 10⁻¹⁰
  4. D4 10⁻¹⁰

Correct answer

B. 4 10⁻¹²

Step-by-step solution

The sparingly soluble salt AX ₂ dissociates according to: AX ₂(s) A ²⁺(aq) + 2 X ⁻(aq) For a solubility of s = 1 10⁻⁴~ mol~dm⁻³ , the ion concentrations are [ A ²⁺ ] = s and [ X ⁻ ] = 2s The solubility product is given by K_ sp = [ A ²⁺ ] [ X ⁻ ]^2 Substituting yields K_ sp = (s)(2s)^2 = 4s^3 With s = 1 10⁻⁴ , we obtain K_ sp = 4 (1 10⁻⁴)^3 = 4 10⁻¹² Final answer: B

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