MHT CET202520 Apr 2025Evening ShiftChemistryIonic EquilibriumActual
The solubility of salt BA ₂ is 4 10⁻⁴ ~mol~ dm ⁻³ . What is solubility product of the salt?
Options
- A1.55 10⁻⁸
- B2.56 10⁻¹⁰
- C3.60 10⁻⁸
- D6.41 10⁻¹⁰
Correct answer
B. 2.56 10⁻¹⁰
Step-by-step solution
Solubility product of BA ₂ The dissociation equilibrium is BA ₂(s) B ²⁺(aq) + 2 A ⁻(aq) . The solubility product expression is K_ sp = [ B ²⁺][ A ⁻]^2 . For a solubility of s , the ion concentrations are [ B ²⁺] = s and [ A ⁻] = 2s . Substituting gives K_ sp = (s)(2s)^2 = 4s^3 . Given s = 4 10⁻⁴ mol dm ⁻³ , we compute: K_ sp = 4 (4 10⁻⁴)^3 = 4 (64 10⁻¹²) = 256 10⁻¹² = 2.56 10⁻¹⁰ . This matches option B. Final answer: B