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MHT CET202520 Apr 2025Morning ShiftChemistryIonic EquilibriumActual

Solubility of Ca ₃ ( PO ₄ )₂ is 'S' mol dm ⁻³ . Find solubility product.

Options

  1. AS^5
  2. B108 ~S ^5
  3. C54 S^5
  4. D12 S^5

Correct answer

B. 108 ~S ^5

Step-by-step solution

The dissociation equilibrium for Ca ₃ ( PO ₄ )₂ is: Ca ₃ ( PO ₄ )₂ (s) 3 Ca ²⁺ (aq) + 2 PO ₄³⁻ (aq) Let S represent the molar solubility. The equilibrium concentrations become [ Ca ²⁺] = 3S and [ PO ₄³⁻] = 2S . The solubility product expression is K_ sp = [ Ca ²⁺]^3 [ PO ₄³⁻]^2 . Substituting the concentrations yields: K_ sp = (3S)^3 (2S)^2 = 27S^3 4S^2 = 108S^5 The solubility product is B .

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