MHT CET20249 May 2024Evening ShiftChemistryIonic EquilibriumActual
Calculate the solubility of sparingly soluble salt BA ^ in mol dm ⁻³ at 300 K if its solubility product is 4.9 10⁻⁹ at same temperature.
Options
- A5.72 10⁻⁵
- B6.40 10⁻⁵
- C7.00 10⁻⁵
- D7.81 10⁻⁵
Correct answer
C. 7.00 10⁻⁵
Step-by-step solution
aligned & BA _ ( s ) B _ ( aq ) ⁺+ A _ ( aq ) ⁻ & x=1, y =1 & ~K _ sp =x^x y ^ y S ^ x+y =(1)^1(1)^1 ~S ¹⁺¹= S ^2 & ~S = K _ sp = 4.9 10⁻⁹ aligned aligned & = 49 10⁻¹⁰ & =7.00 10⁻⁵ M aligned