MHT CET20242 May 2024Evening ShiftChemistryIonic EquilibriumActual
Calculate the solubility product of sparingly soluble salt BA at 300 K if its solubility is 9.1 10⁻³ moldm ⁻³ at same temperature.
Options
- A9.635 10⁻⁵
- B9.012 10⁻⁵
- C8.281 10⁻⁵
- D7.816 10⁻⁵
Correct answer
C. 8.281 10⁻⁵
Step-by-step solution
aligned & BA _ ( s ) B _ ( aq ) ⁺+ A _ ( aq ) ⁻ & Here, x=1 and y =1 & ~K _ sp =x^x y^y ~S ^ x+y =(1)^1(1)^1 ~S ¹⁺¹= S ^2 & ~K _ sp = (9.1 10⁻³ )^2 & ~K _ sp =8.281 10⁻⁵ aligned