MHT CET202121 Sep 2021Evening ShiftChemistryIonic EquilibriumActual
The pH of 0.005 M KOH is 9.95. Calculate the [ OH ⁻ ]
Options
- A6.71 10⁻⁴ M
- B1.12 10⁻⁴ M
- C4.45 10⁻⁵ M
- D8.91 10⁻⁵ M
Correct answer
D. 8.91 10⁻⁵ M
Step-by-step solution
aligned & P ^ H + P ^ OH =14 & P ^ OH =14-.9 .95 & =4.05 & P ^ OH =- ₁₀ [ OH ⁻ ] & [ OH ⁻ ]=10^ - P ^ OH =10^ -4.05 & =10^ -5+0.95 =10⁻⁵ 10^ 0.95 =8.91 10⁻⁵ M aligned