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MHT CET202121 Sep 2021Evening ShiftChemistryIonic EquilibriumActual

The pH of 0.005 M KOH is 9.95. Calculate the [ OH ⁻ ]

Options

  1. A6.71 10⁻⁴ M
  2. B1.12 10⁻⁴ M
  3. C4.45 10⁻⁵ M
  4. D8.91 10⁻⁵ M

Correct answer

D. 8.91 10⁻⁵ M

Step-by-step solution

aligned & P ^ H + P ^ OH =14 & P ^ OH =14-.9 .95 & =4.05 & P ^ OH =- ₁₀ [ OH ⁻ ] & [ OH ⁻ ]=10^ - P ^ OH =10^ -4.05 & =10^ -5+0.95 =10⁻⁵ 10^ 0.95 =8.91 10⁻⁵ M aligned

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