The pH of a 0.1 M solution of NH ₄ OH (having K_ b =1.0 10⁻⁵ ) is equal to

Step-by-step solution

aligned [ OH ⁻ ] &= K_ b C &= 1 10⁻⁵ 10⁻¹ = 10⁻⁶ =10⁻³ K_ w &= [ H ⁺ ] [ OH ⁻ ] 10⁻¹⁴ &= [ H ⁺ ] [10⁻³ ] [ H ⁺ ] &=10⁻¹¹ Hence, pH &=- H ⁺ &=- (1 10⁻¹¹ )=11 aligned