MHT CET2007ChemistryIonic Equilibrium
The pH of a 10⁻⁸ molar solution of HCl in water is
Options
- A8
- Bbetween 7 and 8
- Cbetween 6 and 7
- DNone of these
Correct answer
C. between 6 and 7
Step-by-step solution
pH =- [ H ⁺ ]=- 10⁻⁸=8 It is not possible for acid, so it is [ H ⁺ ] , the [ H ⁺ ] of water is also added. Total [ H ⁺ ] in solution aligned &= [ H ⁺ ] of HCl + [ H ⁺ ] of water &= (1 10⁻⁸+1 10⁻⁷ ) M &=(1+10) 10⁻⁸=11 10⁻⁸ M pH &=- [ H ⁺ ] &=- 11 10⁻⁸ &=- 11+8 10 &=-1.0414+8=6.9586 aligned