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MHT CET202526 Apr 2025Evening ShiftChemistryp Block Elements (Group 15, 16, 17 & 18)Actual

What is oxidation state of xenon in xenonmonooxytetrafluoride?

Options

  1. A+2
  2. B+4
  3. C+6
  4. D+8

Correct answer

C. +6

Step-by-step solution

The oxidation state of xenon in xenonmonooxytetrafluoride ( XeOF₄ ) is determined by considering the known oxidation states of oxygen and fluorine. Oxygen typically has an oxidation state of -2 , and fluorine is always -1 in compounds. Since XeOF₄ is neutral, the sum of the oxidation states is zero. Let x be the oxidation state of xenon. The equation becomes: x + (-2) + 4(-1) = 0 Simplifying: x - 2 - 4 = 0 Thus, x - 6 = 0 and x = +6 . The oxidation state of xenon is +6 , corresponding to answer choice C.

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