Calculate the density of an element having molar mass 225 g mol ⁻¹ forming bcc structure [a^3 N_A = 75 cm ^3 mol ⁻¹]

Step-by-step solution

For a body-centered cubic (bcc) structure, the number of atoms per unit cell is Z = 2 . The formula for the density of a unit cell is given by: d = Z M a^3 N_A Substituting the given values Z = 2 , M = 225 g mol ⁻¹ , and a^3 N_A = 75 cm ^3 mol ⁻¹ : d = 2 225 75 d = 450 75 = 6.0 g cm ⁻³ Answer: 6.0 g cm ⁻³