Calculate the mass of nonvolatile solute dissolved in 0.3 dm ^3 water having osmotic pressure 0.1 atm at 300 K. [Molar mass of solute = 328 g mol ⁻¹ , R = 0.082 dm ^3 atm K ⁻¹ mol ⁻¹ ]

Step-by-step solution

The osmotic pressure is given by the formula: = W M V R T Rearranging for the mass of the solute W : W = M V R T Substituting the given values: W = 0.1 328 0.3 0.082 300 W = 9.84 24.6 W = 0.4 g Answer: 0.4 g