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MHT CET202619 April 2026Morning ShiftChemistrySolutionsActual

van't Hoff factor for BaCl ₂ is 2.47 , calculate the percentage dissociation of in its aqueous solution.

Options

  1. A25.6 %
  2. B35.7 %
  3. C73.5 %
  4. D13.6 %

Correct answer

C. 73.5 %

Step-by-step solution

The dissociation reaction of BaCl ₂ is: BaCl ₂ Ba ²⁺ + 2 Cl ⁻ The number of ions produced per formula unit, n = 3 . The relation between van't Hoff factor i and degree of dissociation is: i = 1 + (n - 1) Substituting the given values: 2.47 = 1 + (3 - 1) 2.47 = 1 + 2 2 = 1.47 = 0.735 Percentage dissociation = 100 = 73.5 %

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