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MHT CET202617 April 2026Morning ShiftChemistrySolutionsActual

Calculate the molar mass of nonvolatile solute when 4 g of it is dissolved in 100 g solvent that boils at 319.4 K [ K_b = 2.4 K kg mol ⁻¹ ; B.P of pure solvent = 319 K]

Options

  1. A220 gmol ⁻¹
  2. B230 gmol ⁻¹
  3. C240 gmol ⁻¹
  4. D250 gmol ⁻¹

Correct answer

C. 240 gmol ⁻¹

Step-by-step solution

Elevation in boiling point is given by T_b = T_b - T_b^0 T_b = 319.4 - 319 = 0.4 K Using the formula for elevation in boiling point: T_b = K_b m = K_b w₂ 1000 M₂ w₁ Substituting the given values: 0.4 = 2.4 4 1000 M₂ 100 0.4 = 96 M₂ M₂ = 96 0.4 = 240 g mol ⁻¹ Answer: 240 gmol ⁻¹

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