18 g of glucose (molar mass = 180 g/mol) is dissolved in water to prepare 500 ml solution at 15^ C . Calculate the osmotic pressure of the solution. [ R = 0.0821 L atm K ⁻¹ mol ⁻¹ ]

Step-by-step solution

Number of moles of glucose, n = 18 180 = 0.1 mol Volume of solution, V = 500 ml = 0.5 L Temperature, T = 15 + 273 = 288 K Osmotic pressure is given by = CRT = n V RT Substituting the values: = 0.1 0.5 0.0821 288 = 0.2 0.0821 288 = 4.72896 atm 4.73 atm Answer: 4.73 atm