Calculate the boiling point of an aqueous solution containing 18 g glucose in 100 g water if the molal elevation constant of water is 0.5 K kg mol ⁻¹ . [Molar mass of glucose = 180 g mol ⁻¹ and boiling point of water = 100 ^ C ]

Step-by-step solution

Moles of glucose = 18 180 = 0.1 mol Mass of water = 100 g = 0.1 kg Molality of the solution, m = 0.1 0.1 = 1 mol kg ⁻¹ Elevation in boiling point, T_b = K_b m T_b = 0.5 1 = 0.5 ^ C Boiling point of the solution = 100 ^ C + 0.5 ^ C = 100.5 ^ C Answer: 100.5 ^ C