The partial pressure of a gas at 25^ C is 0.18 atm, calculate the concentration of the gas dissolved at the same temperature, If K_H is 0.15 mol dm ⁻³ atm ⁻¹

Step-by-step solution

According to Henry's law, the concentration of a dissolved gas is directly proportional to its partial pressure. C = K_H P Given: P = 0.18 atm K_H = 0.15 mol dm ⁻³ atm ⁻¹ Substituting the values: C = 0.15 0.18 C = 0.027 mol dm ⁻³ Since 1 mol dm ⁻³ = 1 M , the concentration is 0.027 M . Answer: 0.027 M