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MHT CET20255 May 2025Evening ShiftChemistrySolutionsActual

Calculate the solubility of gas in solvent at 25^ C and 0.8 atm if Henry's law constant for solvent is 6.8 10⁻⁴ ~mol~ dm ⁻³ ~atm ⁻¹ .

Options

  1. A5.88 10⁻⁴ M
  2. B6.12 10⁻⁴ M
  3. C5.44 10⁻⁴ M
  4. D6.48 10⁻⁴ M

Correct answer

C. 5.44 10⁻⁴ M

Step-by-step solution

Using Henry's Law, the solubility S of a gas is given by S = K_H P_ gas , where K_H = 6.8 10⁻⁴ , mol , dm ⁻³ , atm ⁻¹ and P_ gas = 0.8 , atm . Substituting yields S = (6.8 10⁻⁴) 0.8 = 5.44 10⁻⁴ , mol , dm ⁻³ . This corresponds to option C .

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