Calculate vapour pressure of volatile liquid A at given temperature if mole fraction and vapour pressure of volatile liquid B are 0.4 and 900 mm Hg respectively [ P _ total =600 ~mm Hg ]

Step-by-step solution

Vapor pressure of volatile liquid A The mole fraction of component A is determined from the binary composition: X_A = 1 - X_B = 1 - 0.4 = 0.6 . Applying Raoult's law for the total vapor pressure, P_ total = X_A P_A^0 + X_B P_B^0 . Substituting known values: 600 = 0.6 P_A^0 + (0.4)(900) . Solving for P_A^0 : 600 - 360 = 0.6 P_A^0 240 = 0.6 P_A^0 P_A^0 = 240 0.6 = 400 The vapor pressure of volatile liquid A is 400 mm Hg .