When 0.01 mole of nonvolatile solute is dissolved in certain solvent calculate the mass of solvent in kg if T _ b =0.6 ~K and K _ b for solvent =2 ~K ~kg ~mol ⁻¹

Step-by-step solution

The boiling point elevation T_b is related to molality m by the colligative property formula T_b = K_b m , where T_b = 0.6 K and K_b = 2 K kg mol ⁻¹ . Molality is defined as m = n W_ solvent , with n = 0.01 mol . Substituting gives T_b = K_b n W_ solvent . Solving for the solvent mass yields W_ solvent = K_b n T_b = (2)(0.01) 0.6 = 0.03333 kg , which rounds to 0.033 kg with two significant figures. This matches option C . The final answer is C .